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Mathematics 11 Online
OpenStudy (anonymous):

analyze and sketch the graph of f(x)=(x^2+1)/(x^2-4). Write the domain, asymptotes, local extrema and inflection point if any.

OpenStudy (anonymous):

We can factor out the denominator as follows (x+2)(x-2)

OpenStudy (anonymous):

2,-2 are your verticle retricemtote

OpenStudy (anonymous):

how to find the domain and point of inflection

OpenStudy (anonymous):

domain is everywhere except 2,-2 For inflection point and extrema you will need to take derivative of the function

OpenStudy (anonymous):

Do you know how to take derivative?

OpenStudy (anonymous):

yes then after taking derivative what shall i do

OpenStudy (anonymous):

The first derivative function F'[x], find out where it is zero; this is where extrema are located. For inflection point take derivative again F''[x], and find out where the function is zero; This is your inflction point

OpenStudy (anonymous):

derivative is ((x^2-4)(2x)-(x^2+1)(2x))/(x^2-4)^2

OpenStudy (anonymous):

so i equated it to zero..

OpenStudy (anonymous):

from which i get x=0

OpenStudy (anonymous):

then what shall I do?

OpenStudy (anonymous):

Then the extrema is at x=0

OpenStudy (anonymous):

you can find the inflection point

OpenStudy (anonymous):

it says to find local extrema is that the local extrema value.

OpenStudy (anonymous):

To find local extrema, create a number line from negative infinity to positive, investigate at critical points, the point where first derivative goes from pos to neg or vice versa: local extrema.

OpenStudy (anonymous):

time traveler?

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