Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

The amount of a drug in a person's bloodstream can be modeled with exponential decay. Suppose that, in 3 hours, 18% of the drug is removed from the bloodstream. What is the half-life of the drug? A) 8.1 hours B) 8.7 hours C) 9.3 hours D) 9.9 hours E) 10.5 hours

OpenStudy (anonymous):

E. Use the exponential decay formula

OpenStudy (anonymous):

Can you show me how to set it up?

OpenStudy (anonymous):

first write the formula for exponential decay: I'm going to use my own variables for convience F=Ae^(kt)

OpenStudy (anonymous):

F=amount you have A=amount you start with k=constant t=time elapsed

OpenStudy (anonymous):

what you have to do first is find k, so using 3 hours and 18% we find k

OpenStudy (anonymous):

assume you start with 100% so A=1 F=1-.18=.82 <---- this is cause you remove .18 from the blood, leaving you with .82

OpenStudy (anonymous):

so you have .82=1e^(3k)

OpenStudy (anonymous):

solve for k

OpenStudy (anonymous):

then plug k into the equation. this time F=.5 since you are left with half the amount and t is what you are trying to find.

OpenStudy (anonymous):

and that give me 10.5?

OpenStudy (anonymous):

how do I solve for K? im sorry

OpenStudy (anonymous):

.82=1e^(3k) Ln(.82)=3k k=Ln(.82)/3

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!