The amount of a drug in a person's bloodstream can be modeled with exponential decay. Suppose that, in 3 hours, 18% of the drug is removed from the bloodstream. What is the half-life of the drug? A) 8.1 hours B) 8.7 hours C) 9.3 hours D) 9.9 hours E) 10.5 hours
E. Use the exponential decay formula
Can you show me how to set it up?
first write the formula for exponential decay: I'm going to use my own variables for convience F=Ae^(kt)
F=amount you have A=amount you start with k=constant t=time elapsed
what you have to do first is find k, so using 3 hours and 18% we find k
assume you start with 100% so A=1 F=1-.18=.82 <---- this is cause you remove .18 from the blood, leaving you with .82
so you have .82=1e^(3k)
solve for k
then plug k into the equation. this time F=.5 since you are left with half the amount and t is what you are trying to find.
and that give me 10.5?
how do I solve for K? im sorry
.82=1e^(3k) Ln(.82)=3k k=Ln(.82)/3
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