Question

sqrt x+2+sqrt x=4
lol i keep asking for help on this

Answer 1

is that sqrt(x) + 2 or sqrt(x+2)

Answer 2

well if its the former, x = 1
if the latter, x =49/16

Answer 3

x=49/16 can you explain how you got this please?

Answer 4

\[\sqrt{x+2} + \sqrt{x} = 4\]
\[\iff \sqrt{x+2} = 4-\sqrt{x} \]
Squaring both sides yields:
\[x+2 = 16 - 8\sqrt{x} + x \implies \sqrt x = \frac{7}{4} \]
And squaring gives the result.

Note, squaring can produce spurious roots, so we must check this back in the original equation, and see that it holds.

Answer 5

16-8sqrt x+x can you explain that more

Answer 6

(a-b)^2 = a^2 - 2ab + b^2

let a = 4 , b = sqrt(x)

Answer 7

You're welcome. ¬_¬

Answer 8

is this a formula (a-b)^2 = a^2 - 2ab + b^2

Answer 9

Not a formula so much - well, it is an identity, but it's more just common sense of expanding brackets.

Answer 10

um one more thing\[\sqrt{x+2} +\sqrt{x-4}\rightarrow \sqrt{x+2}-4-\sqrt{x}\]
how did the sqrt of x become negative when you move it

Answer 11

Errr, what? That didn't happen, at all. Assuming your question was right, the 4 was never under the root... and was on the other side.

Answer 12

i meant \[\sqrt{x+2}+\sqrt{x} -4\]

Answer 13

Im still confused .......

Answer 14

Im still confused .......