Question

Help me once again please:

3+5i
-----
1-2i

Answer 1

what are we solving for?

Answer 2

um question is "Evaluate the following"

Answer 3

its that thing where i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1

Answer 4

you could multiply by conjugate to get rid of i in the denominator
\[\frac{(3+5i)(1+2i)}{(1-2i)(1+2i)}\]

Answer 5

then expand? the problem and solve correct?

Answer 6

yes
you should get (11i -7)/5

Answer 7

i got the 11i-5 but where does the /5 come from?

Answer 8

when you multiply the bottom
1 -2i +2i -4i^2
1-4i^2
1-4(-1)
1+4
5

Answer 9

Oh so multiplying both top and bottom doesn't cancel out the bottom. I see where i missed up, thank you very much :)