Find the product, if possible. BA, if A= [-1 -2 -3] [-5 -3 5] [-4 -4 -1] B= [-2 4 2] [3 2 3] [1 5 4]
since this is a 3*3 matrix multiplication you can find the product
the number on the row 1 column 1 can be calculated by multiplyting the entries in the column 1 in B and the row 1 in a as such (-2)(-1) + (4)(-5)+(2)(-4) = 10
to it looks like this so far [10 ] [ ] [ ]
to find row2 column1 (usually noted as..\[a_{21}\])
you multiply [3 2 3] by [-1] [-5] [-4] so you will get (3)(-1)+(2)(-5)+(3)(-4) = -25
so you will get [10 ] [25 ] [ ]
you just keep doing this until everything is filled out
oops I meant -25
also, the first number was actually -26 when I recalculated it
the answer should be [-26 -16 24] [-25 -24 -2] [-42 -33 18]
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