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Mathematics 7 Online
OpenStudy (anonymous):

Find the product, if possible. BA, if A= [-1 -2 -3] [-5 -3 5] [-4 -4 -1] B= [-2 4 2] [3 2 3] [1 5 4]

OpenStudy (yuki):

since this is a 3*3 matrix multiplication you can find the product

OpenStudy (yuki):

the number on the row 1 column 1 can be calculated by multiplyting the entries in the column 1 in B and the row 1 in a as such (-2)(-1) + (4)(-5)+(2)(-4) = 10

OpenStudy (yuki):

to it looks like this so far [10 ] [ ] [ ]

OpenStudy (yuki):

to find row2 column1 (usually noted as..\[a_{21}\])

OpenStudy (yuki):

you multiply [3 2 3] by [-1] [-5] [-4] so you will get (3)(-1)+(2)(-5)+(3)(-4) = -25

OpenStudy (yuki):

so you will get [10 ] [25 ] [ ]

OpenStudy (yuki):

you just keep doing this until everything is filled out

OpenStudy (yuki):

oops I meant -25

OpenStudy (yuki):

also, the first number was actually -26 when I recalculated it

OpenStudy (yuki):

the answer should be [-26 -16 24] [-25 -24 -2] [-42 -33 18]

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