How to solve abs(e^(2x) - (1/x+2)) = 2

Question

anonymous · Answer

$$| e ^{2x} - 1/(x+2)| = 2$$
absolute value mean that it's  =( 2 )  or  =( -2 ) so, solve for both and you'll have yur answer.

got it ?

peace · Answer

yea i'm trying to do that, but i'm not really getting anywhere

anonymous · Answer

Ok. So, for the first equality:
$$e ^{2x} - 1/(x+2) = 2$$
you can take out the fraction by inverting everything:$$e^{-2x} - (x+2) = 1/2$$$$e^{-2x} - x = 5/2$$
to eliminate the {e}, multiply everything by Natural Log (ln)$$-2x - \ln x = \ln (5/2)$$
solve for x and there might be more than 1 solution

peace · Answer

how do i go on from -2x = ln (5x/2)

anonymous · Answer

sorry, i can't remember/find how to solve :/

peace · Answer

aw it's ok, thanks for your help though :)

anonymous · Answer

np, if i find somewhere i'll post it here (: