Question

How to solve abs(e^(2x) - (1/x+2)) = 2

Answer 1

\[| e ^{2x} - 1/(x+2)| = 2\]
absolute value mean that it's =( 2 ) or =( -2 ) so, solve for both and you'll have yur answer.

got it ?

Answer 2

yea i'm trying to do that, but i'm not really getting anywhere

Answer 3

Ok. So, for the first equality:
\[e ^{2x} - 1/(x+2) = 2\]
you can take out the fraction by inverting everything:\[e^{-2x} - (x+2) = 1/2\]\[e^{-2x} - x = 5/2\]
to eliminate the {e}, multiply everything by Natural Log (ln)\[-2x - \ln x = \ln (5/2)\]
solve for x and there might be more than 1 solution

Answer 4

how do i go on from -2x = ln (5x/2)

Answer 5

sorry, i can't remember/find how to solve :/

Answer 6

aw it's ok, thanks for your help though :)

Answer 7

np, if i find somewhere i'll post it here (: