Simplify. 2x^4-3x^3-11x^2-40x-1 all over x-4

Question

anonymous · Answer

You want to write in the form of quotient and a remainder?

anonymous · Answer

sure

anonymous · Answer

If so, then (using long division):
$${2x^4-3x^3-11x^2-40x-1 \over x-4}=2x^3+5x^2+9x-4-{17 \over x-4}$$

anonymous · Answer

how did u get that????

anonymous · Answer

Do you know how to do long division?

anonymous · Answer

yes

anonymous · Answer

you have to factor the numerator, and one of those factors should be (x-4) which can cancel out.

anonymous · Answer

Okay, then do it till you stop at the point where you have a reminder of -17. At this point, you will have a quotient equal to 2x^3+5x^2+9x-4. And a reminder of -17. The original expression is equal to = the quotient +the reminder/divisor.

anonymous · Answer

@halcyon_m: it wouldn't work that way, since x-4 is not a factor of the numerator.

anonymous · Answer

thanks