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√7(3-2√7)
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if you have a fraction with a sqrt on the denominator (bottom part). You have to multiply and devide your fraction by the same sqrt:\[-2/\sqrt{7}\]\[(-2/\sqrt{7}) * (\sqrt{7}/\sqrt{7}) = (-2\sqrt{7} / 7)\]
parenthesis first:\[(3-2\sqrt{7}/7) = (21-2\sqrt{7})/7\]
thx
wait, i dont get it
for last multiply:\[\sqrt{7} * (21-2\sqrt{7})/7 = (21\sqrt{7}- 2*7) / 7 = (21\sqrt{7} - 14)/7\]
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you can simplify by factoring 21 and 14:\[[7*(3\sqrt{7}-2)]/7 = (3\sqrt{7}-2)\]
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