Question

find the area of the region enclosed between the graphs of y=(64x)^(1/4) and y=x

Answer 1

First you need to find the intersection of those graphs so you know what your limits of integration will be

Answer 2

64(x)^(1/4)=x, solving for x yields the integration intervals.

Answer 3

Then integrate ((64)(x^(1/4)) - x) on that interval.

Answer 4

x = 0, 256

Answer 5

\[\int\limits_{0}^{256}(64x^.25-x)dx\]

Answer 6

19660.8