Question

Find dy/dx of ln(x*y^2)=24
A. -2x/y
B. -y/2x
C. -y/2
D. -e^(-.5)

Answer 1

A

Answer 2

could you explain how you did it? I tried, and I keep on getting the wrong answer.

Answer 3

Solve the function for y, and get
y = e^24/sqrt(x*e^24)
Differentiate in respect to y

Answer 4

oh, nvm. I accidentally messed up a multiplication.

Answer 5

I get B

Answer 6

\[dy/dx = (1/(x*y^2))(y^2+2yx(dy/dx)) =0\]
\[dy/dx = -1/x*(y/2) = -y/(2x)\ = -2x/y] so yeah its A
my bad

Answer 7

\[dy/dx = -1/x*y/2 = -2x/y\] A