Question

solve the quadratic equation by completing the squares
2x^2 +4x+7=0
a. x=-2+/-sqrt /2 b. no real solution c. x=-2+/-sqrt14/2 d. x=+/- sqrt7

Answer 1

No real solutions

Answer 2

And you can do that by looking at the discriminant

Answer 3

Do you know how to look at the discrimant and find whether it is real or complex?

Answer 4

no i dont how is that done?

Answer 5

Do you want to know, or you are satisfied with the answer

Answer 6

lol id like to know please

Answer 7

factor out the 2
x^2 +2x +7/2 = 0
take half the second coefficient and square it
(x+1)^2 -1 +7/2 = 0
(x+1)^2 = -5/2
x+1 = sqrt(-5/2)
sqrt of neg num is non-real answer

Answer 8

For any quadratic equation \[ax^2+bx+c\] if
\[(b^2-4ac)\]<0
then the equation has no real roots

Answer 9

lol thats blank above

Answer 10

Just remember this and it will work always

Answer 11

Did you understand that?

Answer 12

any problem?

Answer 13

no im reading it trying to understand
thanks a bunch everyone :)

Answer 14

yes i get it