Question

the center of the circle defined by 2x^(2)+2y^(2)+4x-12y-30=0 is
a) (-1,3)
b) (2,-6)
c) (-2,6)
d) (1,-3)

Answer 1

I'm guessing I divide everything by 2 to begin with, but what happens to the squares?

Answer 2

-1,3

Answer 3

You just have to turn everything into a more usable form : (x-a)^2-(y-b)^2=radius^2, where a and b are the coordinates of the circle's center :) Hope that helped

Answer 4

adams right

Answer 5

(x-a)^2+(y-b)^2=r^2 is the form.

Answer 6

So mainly you should try to complete the squares.

Answer 7

Do you know how to "complete the squares" for this problem?