Question

2 + q^2/200 = 4000/p^2 differentiate implicitly

Answer 1

to find dq/dp

Answer 2

yeh still not enough info , are we meant to assume that q ia a function of p

Answer 3

sry...q is suppose demand for a good and p is the price of the good....

Answer 4

yeh, so q is a function of p

Answer 5

so it is the exact same as differentiating 2 + y^2 / 200 = 4000/x^2

where y=q=dependant variable

Answer 6

\[2 + \frac{y^2}{200} = 4000x^{-2}\]

Answer 7

diff wrt x ( and x=p )

0 + (2y / 200 ) (dy/dx ) = -8000x^-3

Answer 8

so dy/dx = -80000x^-3 / y

Answer 9

\[\frac{dy}{dx} = \frac{-80000}{x^3 y}\]

Answer 10

now replace y with q, and x with p

Answer 11

ohhh ok thanks very much...

Answer 12

wait, should be 800 000 on the top

Answer 13

8000 x100 =800 000

Answer 14

ok cool...i undersatnd your method though thats what i needed help with....