Question

simplify: (sin^2x)/(sec^2x-1)

Answer 1

help :(

Answer 2

sin^2 + cos^2 = 1

dividing through by cos^2

tan^2 + 1 = sec^2

therefore sec^2 -1 = tan^2

Answer 3

so the question becomes\[\frac{\sin^2(x)}{\tan^2(x)}\]

Answer 4

\[= \sin^2(x) \times \frac{\cos^2(x)}{\sin^2(x)}\]

Answer 5

\[= \cos^2(x)\]

Answer 6

remember that \[\tan(x) = \frac{\sin(x)}{\cos(x)}\]

then when divide by something it is the same as flipping that"something", and multiplying