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Mathematics 10 Online
OpenStudy (anonymous):

anyone have questions ask me :D

OpenStudy (anonymous):

I have one!

OpenStudy (anonymous):

and what is it?

myininaya (myininaya):

no you cannot go to the bathroom

OpenStudy (anonymous):

How could you position 100 circles to intersect the maximum number of times?

OpenStudy (anonymous):

your teacher must be a feather cuz i dont know that one

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

no ideas on how to start it?

OpenStudy (anonymous):

I think it's a good question dinabina. Does the question say anything about radius of the circles; are they all of the same size?

OpenStudy (anonymous):

Nothing that all it asks... thats why I am not sure where to begin.

OpenStudy (anonymous):

same radius but different centers... I think that is used to throw me off tho...

OpenStudy (anonymous):

well, the question is actually asking you, somehow, to determine the center!

OpenStudy (anonymous):

centers*

OpenStudy (anonymous):

I do know a circle intersects another circle twice

OpenStudy (anonymous):

If all circles have the same radius, then they intersect maximum number of times, when you put each one in the top of the others.

OpenStudy (anonymous):

Do you think this will be a formula answer?

OpenStudy (anonymous):

Does my last answer make sense to you?

OpenStudy (anonymous):

umm...they intersect maximum number of times?... no

OpenStudy (anonymous):

What is an intersection?!

OpenStudy (anonymous):

cross.. meet at a point

OpenStudy (anonymous):

if you have circle 1 with the same radius as circle 2. And you draw circle with the same center as circle 2. Then they will have infinitely many intersection points; they actually intersect for all points in the two circles.

OpenStudy (anonymous):

ok yes... that makes sense

OpenStudy (anonymous):

That's only valid if they have the same radius.

OpenStudy (anonymous):

If they are with different radii, then they will not intersect at all when they have the same center.

OpenStudy (anonymous):

How are you figuring this out? Are these rules of circles?

OpenStudy (anonymous):

Not really, just think about it. It's very clear.

OpenStudy (anonymous):

ok so these are same radius different centers... how would I poistion 100 circles?

OpenStudy (anonymous):

oh the question says they have to have different centers?!

OpenStudy (anonymous):

Is this going to be a picture answer or a formula answer?..... yeah same radius different centers.... but the question just says how would you position 100 circles to intersect the maximum number of times.

OpenStudy (anonymous):

It was an a., b., c. type question. so I am not sure if it even pertains

OpenStudy (anonymous):

I think the max will be if all of them intersect at the center of some other circle.

OpenStudy (anonymous):

I would roughly say that each circuit has to intersect the others at two points.

OpenStudy (anonymous):

each one of the other circuits at two points*

OpenStudy (anonymous):

Is the question asking about the number of maximum intersection points?

OpenStudy (anonymous):

no just how to position 100 circles to intersect the maximum number of times

OpenStudy (anonymous):

Ok, as I say in a position such that each circuit would intersect twice with each one of the 99 remaining circuits.

OpenStudy (anonymous):

I am not sure of that answers the question.

OpenStudy (anonymous):

ok... I understand that....

OpenStudy (anonymous):

What do you think polpak?

OpenStudy (anonymous):

One sec

OpenStudy (anonymous):

Take your time!

OpenStudy (anonymous):

number of total points of intersection of n congruent circles = 2C(n, 2) 100 circles intersect in 2C(100, 2) = 400 points Does this look wack?

OpenStudy (anonymous):

100 times 2 = 200 a circles intersects twice... ???

OpenStudy (anonymous):

i hax a question

OpenStudy (anonymous):

Ok, so I think for positioning them you just have to arrange their centers around some point at intervals of \(2\pi/100\) radians a distance less than r from that point (where r is the radius of each circle).

OpenStudy (anonymous):

that will space them evenly at any rate.

OpenStudy (anonymous):

i haz a question, can you answer it plzzz????

OpenStudy (anonymous):

while still having each circle intersecting each other circle twice.

OpenStudy (anonymous):

Oh wow... so would that formula be the answer or plug in the numbers

OpenStudy (anonymous):

Thank you

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