When a chunk of matal is dropped into a container of water the water level rises 3.4cm. The container is shaped like a cylinder with a radius of 3cm. What is the volume of the metal.

Show work please

Question

When a chunk of matal is dropped into a container of water the water level rises 3.4cm. The container is shaped like a cylinder with a radius of 3cm. What is the volume of the metal.

Show work please<33

anonymous · Answer

pi r^2 h

anonymous · Answer

Volume of cylinder = (Area of the Base)*(Height)

The base of a cylinder is a circle so,
Area of a circle = (pi)r^2

The initial Height is X, after the metal is dropped it turns to x+3.4

anonymous · Answer

soo how would you find the volume of that metal? or the inital height?

anonymous · Answer

it is same as volue of water risen in container

anonymous · Answer

how would you find that out?

anonymous · Answer

$$V' = \pi (3^{3})h = 9{\pi}h$$$$V'' = \pi(3^{3})(h+3) = 9h{\pi}+27{\pi}$$
$$V'' - V' = Vmetal$$$$9h{\pi}+27{\pi} - 9{\pi}h = 27{\pi}$$

anonymous · Answer

Where V' = original volume
          V'' = after metal volume

anonymous · Answer

oh okay, but on the first equation for the after metal volume shouldnt it be (h+3.4)? or no..

anonymous · Answer

yea, you're right.  instead of 27 it's  30.6

anonymous · Answer

so its 30.6pi?

anonymous · Answer

indeed

anonymous · Answer

Thanks so much I've got it now<3

anonymous · Answer

np