Question

find the derivative of the equation.
h(z) = e[(−z^2)/2]

Answer 1

did you mean e ^ [(−z^2)/2] or e * [(−z^2)/2] ??

Answer 2

the ^ not *... it's e raised to (-z^2)/2

Answer 3

i got to be \[-xe^{{-x^{2} \over 2}} \]

Answer 4

i think you're definitely right - that makes so much sense.. i forgot that the integration of e^x equals itself

Answer 5

thanks for all your help - are you on here often??

Answer 6

haha np. Yea, i'm on summer break now so i'll be here sometimes

Answer 7

awesome - i'm working on problems for my calc 2 final.. so frustrating!

Answer 8

oh boy.... calc SUCKS!!! lol

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Answer 9

haha tell me about it!! this final is our only grade in the class..how do i give medals? i'll totally give you a bunch!!

Answer 10

haha that's even worse. There's a gray bar on every post, on this bar there's a button [give meal] just click on it. Also if you leave your mouse cursor on top of my nickname image, you see my fans lmao

THanks

Answer 11

i can't find it :-(.. i'll try to figure it out i'll be back asking questions later and the next few days.. btw just became a fan! haha thanks!

Answer 12

hahaha alright, thanks. Good luck