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Mathematics 6 Online
OpenStudy (anonymous):

Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x + 5y)^10, n = 4 A. 210x^6y^4 B. 15,000x^7y^3 C. 210x^6y^4 D. 9,765,625y^10 E. 5040x^6y^4

OpenStudy (anonymous):

n=10? I believe??? \

OpenStudy (anonymous):

nevermind... term in the expansion

OpenStudy (anonymous):

which is a different variable rth term of expansion

OpenStudy (anonymous):

I guess I understand how to write it all out just not how to simplify it correctly to get a condensed answer like the ones they provide

OpenStudy (anonymous):

http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut54_bi_theor.htm Look at example 8... if you have problems I'll do it out for you

OpenStudy (amistre64):

pascals triangle

OpenStudy (anonymous):

Ha ha I'm on that site right now trying to work it out lol Does it matter though if it's rth term or nth term?

OpenStudy (anonymous):

doesn't matter coz thats just a variable

OpenStudy (amistre64):

1 1,1 1,2,1 1,3,3,1 1,4,6,4,1 1,5,10,10,5,1 1,6,15,20,15,6,1 1,7,21,35,35,21,7,1 1,8,28,56,70,56,28,8,1 1,9,36,84,126,126,84,36,9,1 1,10,45,120,210, ....

OpenStudy (anonymous):

well if you are following the site, the rth term is 4, the nth term is 10

OpenStudy (amistre64):

120 (x^7) (y^3)

OpenStudy (anonymous):

answer is b though

OpenStudy (amistre64):

120 (x^7) ((5y)^3)

OpenStudy (amistre64):

120.125 x^7 y^3 15000 x^7 y^3

OpenStudy (amistre64):

BBBBBBBBBB

OpenStudy (anonymous):

\[{10 \choose 4 }=210\] 4th term is \[210 x^6 (5y)^4\]

OpenStudy (anonymous):

of course i could be wrong. the 'n=4' is not clear.

OpenStudy (amistre64):

lol..... im prolly wrong :)

OpenStudy (anonymous):

wow ok the answer I got isn't even close to any of these.... I got 100800x^7125y^3....not quite sure what id id wrong

OpenStudy (amistre64):

the 4th term is 120 x^7 y^3 as a standard... tehn you have to account for the coeefs in the original problem....namely the +5 attached to the y

OpenStudy (amistre64):

120 x^7 (5y)^3

OpenStudy (amistre64):

120.125 x^7 y^3 15000 x^7 y^3 :)

OpenStudy (anonymous):

oh ok makes sense ok Can I try another one on my own and have you check it?

OpenStudy (amistre64):

sure; but you can check it with pascals triangle; i posted that first to like half the 10th spot ;)

OpenStudy (anonymous):

ok :)

OpenStudy (anonymous):

ok the problem is: Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x - 2y)^12, n = 6 I got 760x^7y^5 which is definitly not one of my answer choices....

OpenStudy (amistre64):

at 6 eh 12 11 10 9 8 7 x^6 y^6 is gonne be the variable answers

OpenStudy (amistre64):

you got any with ony an x^6 y^6 as an asnswer?

OpenStudy (anonymous):

oh it's cause I used the 12 instead of the six let me try it again....

OpenStudy (amistre64):

ack..you were right with the x and y lol...i lost count :)

OpenStudy (amistre64):

x^7 y^5 is the 6th term

OpenStudy (anonymous):

oh ok so I was right now....idk how I got the 760.... cause that's nowhere close to their choices

OpenStudy (amistre64):

lol..... which choice has the right x and y parts?

OpenStudy (amistre64):

narrow it down if its multiple choice ;)

OpenStudy (anonymous):

- 25,344, but that just doesn't seem right to me oh well I guess

OpenStudy (amistre64):

well lets play detective shall we :) is the - part correct? -2^5 = a negative right? so i believe the negative is right... if its got the right x and y parts, then its a sure shot

OpenStudy (anonymous):

ok well thank you very much!

OpenStudy (anonymous):

Do you know the binomial theorem?! It's quite easy to do it using this theorem.

OpenStudy (anonymous):

learning it I think i just have to keep practicing using cause I get numbers mixed up and stuff

OpenStudy (anonymous):

I see.

OpenStudy (anonymous):

ya it's weird I can find the x and y parts but the number before I somehow lkeep messing up

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