If a stone is tossed from the top of a 190 meter building, the height of the stone as a function of time is given by h(t) = -9.8t2 – 10t + 190, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth’s place; include units in your answer.
geekgirl1988, please review the previous question you asked regarding the application of the discriminant. I made an error which I corrected.
-9.8t^2 - 10t + 190 = 190 t(-9.8t-10) = 0 t=-10/9.8 Thus it will fall after 10/9.8 secs
yes i saw that radar and it is one solution.
I think i did a mistake...sorry!
ok
The equation you need to solve is -9.8t^2 - 10t + 190 = 0
would i use the quadratic formula?
yes
ok on while i solve the problem.
you know the formula right
yes. doing th problem right now. almost done. hold on.
After you do it, just tell me how old are you? So that I can help accordingly, or else i might miss something you may not know
i got x=-3.6 or x=2.6 for my answer. and i am 22.
Right, now the point is can time be negative?
would that answer be no. if so then the answer to the problem would be 2.6 seconds per meter so it would be 494 seconds. or am i wrong.
Yup you are right, btw how did you get that value 494?
2.6*190=494. should i not put that into the answer.
Nope, that doesn't mean anything!
The last part would be 2.667
Join our real-time social learning platform and learn together with your friends!