Question

x^4-37x^2+36
find the factors

Answer 1

let x^4 = t^2

Thus,
t^2 - 37t + 36 = 0

Answer 2

\[(x^2-36)(x^2-1)\]

Answer 3

the roots are 1 and 36

Answer 4

also -1 and -6

Answer 5

Therefore x = \[\pm1 , \pm\]

Answer 6

Sorry I meant roots for t are 1 and 36

Answer 7

Therefore \[x = \pm1 , \pm 6\]

Answer 8

so (x-1)(x+1)(x-6)(x+6)?

Answer 9

oui

Answer 10

Yup right littleice!