Find the angle between the vectors u and v if u = (- 1, 1) and v = (3, 1). Round answer to two decimal places. A. 114.64o B. 115.33o C. 116.57o D. 117.53o E. 117.98o
cos(t) = v.u/|v||u| t = cos^-1(v.u/|v||u|)
The angle between a horizontal line. ( say the x axis) and 1,1 is 45 The angle between the horizontal and 3,1 is 15.
So the angle should be 30
the angle is measured in counter clockwise rotation
ok so amistre.... I have that formula and plugged in my numbers -2/llull llvll
-1,1 3,1 ----- -3+1 = -2 = v.u
right i got that
|v| = sqrt(2); |u| = sqrt(10) = sqrt(20) = 2sqrt(5)
-2 ------- = -1/sqrt(5) right? 2 sqrt(5)
yes when simplified noew I take the arc cos of that
*now
so it's looking like c
cos^-1(-1/sqrt(5)) = .... 116.5650
C is it :)
Join our real-time social learning platform and learn together with your friends!