Question

If f(x) = 3x^2 - x + 2 find [f(a)]^2 please show work

Answer 1

\[f(a) = 3a^2-x+2\]\[[ f(a) ]^2 = [ 3a^2-x+2 ] ^2 = [3a^2-x+2][3a^2-x+2]\]
can you go from here?

Answer 2

typo.. it's supose to be "a" for all x'es

Answer 3

sorry no I can't

Answer 4

\[[3a^2−a+2][3a^2−a+2] = (3a^2)(3a^2)+(3a^2)(-a)+(3a^2)(2)+(-a)(3a^2)+(-a)(-a)+(-a)(2)+(2)(3a^2)+(2)(-a)+(2)(2)\]

Answer 5

it didn't fit here lol

Answer 6

ok i think i understand now

Answer 7

but basically its:
\[[3a^2−a+2][3a^2−a+2] = \]
\[(3a^2)(3a^2)+(3a^2)(-a)+(3a^2)(2)\]\[+(-a)(3a^2)+(-a)(-a)+(-a)(2) \]\[+(2)(3a^2)+(2)(-a)+(2)(2)=\]
\[9a^4 - 3a^3 -3a^3 + 6a^2 -a^2+6a^2-2a-2a+4\]


is that better?