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OpenStudy (anonymous):
2) The population P in 1996 for a state is given along with r, its annual % rate of continuous growth P=8 Millions, r = 2.2% Estimate the population in 2017 = ?
15 years ago
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OpenStudy (anonymous):
\[P(t) = Po(1-r)^t \]\[P(t) = 8(1-0.022)^t \]\[P(t) = 8 (0.978)^t \]\[P(2017-1996) = 8(0.978)^{2017-1996}\]
15 years ago
OpenStudy (anonymous):
so the population in 2017 is?
15 years ago
OpenStudy (anonymous):
you tell me ^^
15 years ago
OpenStudy (anonymous):
\[8(0.978)^{21}\]
15 years ago
OpenStudy (anonymous):
oh I see now
15 years ago
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OpenStudy (anonymous):
1) In 2000 the population of a state was 4 million and growing continuously at a rate of 3.4% per year. Estimate the state’s population in 2005 = ?
15 years ago
OpenStudy (anonymous):
how would I do this one?
15 years ago
OpenStudy (anonymous):
same way... you have Po = 4 million, r = (3.4)/100 and t = 2005 - 2000
15 years ago
OpenStudy (anonymous):
so I would have 4(3.4/100)^5
15 years ago
OpenStudy (anonymous):
sorry i typed the fomula wrong instead of - it's +\[P(t)=Po(1+r)^t\]
15 years ago
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OpenStudy (anonymous):
almost you'd have \[P(t)=4(1+{3.4 \over 100})^5\]
15 years ago
OpenStudy (anonymous):
don't forget to add 1 to the rate r
15 years ago
OpenStudy (anonymous):
oh ok thank you
15 years ago
OpenStudy (anonymous):
np
15 years ago
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