Question

douald has investments totaling 4,000 in two accounts-one a savings account paying 3% interest and the other bond paying 5%. if the annual from the two investment was 180%, how much did he have in invested at each rate?

Answer 1

douald has investments totaling 4,000 in two accounts-one a savings account paying 3% interest and the other bond paying 5%. if the annual from the two investment was 180, how much did he have in invested at each rate?

Answer 2

Let funds deposited into account 1 be A and funds deposited into account 2 be B.

A + B = 4000, since the total amount invested is $4,000.

Since A earns interest at 3% and B earns interest at 5%, we can set up a second equation like this:

A*.03 + B*.05 = 180

Answer 3

ok

Answer 4

So you have A+B=4000
And .03A + .05B=180

Can you solve one of those for A or B? The first one, maybe?

Answer 5

no can u show me how

Answer 6

Let's solve for A by subtracting B from both sides:
A+B=4000
- B
--------------
A =4000-B

Answer 7

Now you can substitute that in for A in the second equation:

.03(4000-B) + .05B = 180

Answer 8

i thought i subtract the like terms

Answer 9

I'm not sure what you mean.

Answer 10

o while ill do it your way

Answer 11

ok wat i do now

Answer 12

Distribute .03:

.03*4000 - .03B + .05B = 180

Answer 13

ok i did it

Answer 14

Okay, what did you get? Then simplify it.

Answer 15

is the answer 120.02

Answer 16

Well, .03*4000 = 120.00. But that is not the answer to the problem. We need to solve for A and B.

Answer 17

ok is u workin it out to

Answer 18

I want you to understand how to get there, I'd rather not just give you the answer.

Answer 19

When you distribute .03:
.03*4000 -.03B +.05B what do you get?

Answer 20

i know hw answer i just said was the wronge answer

Answer 21

.03*4000 -.03B+.05B = 120 + .02B = 180

Subtract 120 from both sides
.02B=60

Divide
60/.02=B=3000

Plug back in to the original equation
A+3000=4000

Therefore A = 1000 and B = 3000

Answer 22

want it be -0.35b=60

Answer 23

then wat do i do next

Answer 24

I worked it all out above.

Answer 25

how much did he have invested at each rate?

Answer 26

I already answered the question.

.03*4000 -.03B+.05B = 120 + .02B = 180

Subtract 120 from both sides
.02B=60

Divide
60/.02=B=3000

Plug back in to the original equation
A+3000=4000

Therefore A = 1000 and B = 3000