what is the slope of (3,3) and (-1,-1)
\[m =\Delta y/\Delta x\]
hey, let x1=3 and y1=3 x2= -1 and y2 = -1 then use the formula, slope(m) = y2-y1/x2-x1= 1
use the formula y=mx + b after poulami's formula
so what is the answer?
m=(3-(-1))/3-(-1))=4/4=1
Slope is 1
what is the slope for (-3,1) and (1,5)
Work it the same way. What are your two y values?
1,5
right, what is the difference between those points, 5-1=???
5-1=4
Yes, 4 is the numerator. Now work out the denominator. What are the x values?
-3-1=-2
Almost. The difference between -3 and +1 if you were at -3 how many units would you have to move to get to +1. We are trying to get the distance from -3 to +1
-3 - 1=-4
so the answer is 4/-4
1-(-3)=1+3=4 We have to go the same direction we went with the y value
so the answer is 4/4 or 1 again.
the slope for (-1,-1) and(3,3) is the slope 2 and 4
What you must do is to label your two points (in your mind) as P1 and P2\[m=(y _{2}-y _{1})/(x _{2}-x _{1})\]
Which point do you want to call P1?
O.K. I will make the assignment (-1,-1) is P1, then (3, 3) is P2 then slope m=(3-(-1))/(3-(-1))=4/4=1 slope is 1
(-3,1) (1,5) (3,3) (-1,-1) all these sides are each what
Join our real-time social learning platform and learn together with your friends!