Question

solve the equation: the square root of x^2-3x+25=x+2

Answer 1

set it =0 and use the quadratic formula.

Answer 2

\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}

Answer 3

\[\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}\]

Answer 4

\[\sqrt{x ^{2}-3x+25}=x+2\]

Answer 5

wow what are you doing? That doesn't look right at all.

Answer 6

thats what the problem is , that s what i have to solve

Answer 7

Do you know what the quadratic formula is?

Answer 8

yeah but you dont use the quadratic formula for this problem

Answer 9

you got to square both sides but after that i have no idea what to do

Answer 10

Why can't you use the quadratic formula?

Answer 11

because this is solving radical equations

Answer 12

But this time you have another value of x aside from x^2

Answer 13

\[(\sqrt{x ^{2}-3x+25})^{2}=(x+2)^{2}\]

Answer 14

that problem is that you took a square root out of nowhere.

Answer 15

This is the first step in solving it , but then i dont know what to do, this is how i have it in my notes and how it has it in the book

Answer 16

a square cancels the square root on the left side

Answer 17

But if you take the square root of one side you have to take the square root of the other side. So that squared thing is pointless.

Answer 18

idk that s how the professor told us to do it

Answer 19

Ok do that square root thing but do it to BOTH SIDES