If |z1 - z2| = k, then find the radius of curvature of the locus arg(z1/z2) = θ
θ in radians
so what does locus z1/z2 mean?
on the argand plane the locus corresponding to amplitude (z1/z2) = θ
the radius of curvature is the circle that matches k, i recall that much
k in what respect??
at any given point along a curve in R3, it can be defined by the rate of curve withi respect to distance traveled along it
the answer in the book says (ksecθ) / 2
yeah thats right but it has to be a quantity..the answers given..i dont get nething else
the radius is te radius of the circle that matches the curvature produced; how to get it i cant recall
something about the tangent vector and the normal vector and hopw they interact
theres one more im posting...
GUYS IAM NOT GETING IT PLZ HELP ME
an = k (ds/dt)^2 <N> but that doesnt seem to help does it lol
ur not getting what??
PLZ SOLVE THIS QUESTION ONCE
acceleration has a 'tangent' and a 'normal component to it; the normal component is modified by k... but the details elude me
why would we need these physical quantities to solve an argand diagram..
salman bhai post ur questions on the left side
lol...dunno, just recollecting what i read the other night about curvature and the radius of curvature
DO U KNOW URDU?????????????
my books all the way out inthe car so...
just hindi bhaijan..lil bit urdu
OK
im quasi proficient in english :)
hahaha..im more proficient in english than hindi..written that is...
salman bhai wts ur question??
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