Question

the value of 2^(1/4).4^(1/8).8^(1/16).16(1/32)........................ is?

Answer 1

2^(1/4+2/8+3/16+.....)

Answer 2

find the sum of AGP series....1/4+2/8+3/16+4/32

Answer 3

2^(13/16)

Answer 4

this is not an AP, the 1st n 2nd term are the same isnt it?

Answer 5

yes it is AGP....

Answer 6

1/2^2 +(1+1)/2^3+(1+2)/2^4+(1+3)/2^5

Answer 7

AGP is airthmatic geomatric series

Answer 8

got it?????

Answer 9

tn=n/2^(n+1)

Answer 10

from tn you have to find Sn. here the series is small so you can add but otherwise you have to use series method.........

Answer 11

whats the series method??

Answer 12

check the page http://www.ilovemaths.com/3sequence.asp

Answer 13

this is an infinite series i guess we gotta use Sn= a/1-r
need to break the question itno that form

Answer 14

no this form will not be applicable........

Answer 15

tn=n/2^(n+1)
\[t _{n+1}=(n+1)/2^{n+2}=n/2^{n+2}+1/2^{n+2}\]
\[t _{n+1}=t _{n}/2+1/2^{n+2}\]
t2=t1/2+1/2^3
t3=t2/2+1/2^4
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.
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adding Sn-t1=Sn/2 +(1/2^3+1/2^4+.........)
Sn/2=t1+(1/2^3+1/2^4....)

Answer 16

Sn/2=1/4+(1/2^3)(1/(1-1/2))
=1/4+1/4
Sn=1

Answer 17

hence 2^1=2

Answer 18

Got it?????

Answer 19

i think u have understood