What is the distance from the point (6,0) to the line y=3x+2?
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OpenStudy (amistre64):
which distance you want? shortest most likly
OpenStudy (amistre64):
the shortest distance is a perpendicular line....
OpenStudy (amistre64):
so to find it, we need the line that is perp to this and the point they intersect
OpenStudy (anonymous):
Possible answers are
4, \[2\sqrt{10} , \sqrt{26} , and\ 3\sqrt{6}\]
so I guess which ever equals one of those
OpenStudy (amistre64):
the perp has a product of slopes that equals -1
3x = -1
x = -1/3
0 = -1/3(6) +b
b = 2
y = (-1/3)x +2
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OpenStudy (amistre64):
these lines meet at:
3x+2 = (-1/3)x +2
3x + 1/3x = 0
10/3x = 0
x = 0
OpenStudy (amistre64):
they appear to meet at the origin...
OpenStudy (amistre64):
they meet at (0,2) if anything lol
OpenStudy (amistre64):
id go with 4
OpenStudy (anonymous):
Per distance formula is \[d= \frac{ \left| ax +by +c \right| }{ \sqrt{a^2 +b^2}}\]
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OpenStudy (amistre64):
im prolly wrong since i guessed that lol
OpenStudy (amistre64):
y = 3x+2 .....
0 = -6/3 +b
0 = -2 +b
b = 2
y = (-1/3)x +2.... that seems to work out
OpenStudy (anonymous):
y= 3x+2
get into general form
3x - y + 2 =0
so this means that a=3 , b=-1 and c=2 in our formulas above, and (x,y) are the coordinates of the point ( 6,0)
so x=6 , y=0
OpenStudy (anonymous):
d= (9 +2 ) / 2 = 4.5 units
OpenStudy (anonymous):
wait thats wrong
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