Question

Could anyone please help me with simplifying radicals? -15

Answer 1

√(-15) is the problem?

Answer 2

\[\sqrt{-15}\]

Answer 3

what is your question?

Answer 4

it is odd and cannot be simplfied

Answer 5

ok so if you break it into it's factors you get √(-1)(3)(5)
√(-1) = i
the rest cannot be simplified so you have i√15 for an answer

Answer 6

√49 is also odd but simplifies to 7 mmolina

Answer 7

so the answer is -1/15

Answer 8

?

Answer 9

no, the answer is: i*srqr(15)

Answer 10

i squared as in india type of i?

Answer 11

\[i*\sqrt{15}\]

Answer 12

hmm never heard of that before. what rule is that derived from?

Answer 13

i is the imaginary unit √(-1) because you cannot take the square root of a negative number.

Answer 14

okay. let me try that...

Answer 15

set in you personal calculator \[\sqrt{-1}\] this will give you an error as the answer. So every time you have an expresion like that you have to write an i in front of the root and make the number inside the root positive.

Answer 16

the entire problem is quadratic formulas which is -1 +/- \[\sqrt{-15}/2\]

Answer 17

then there are no real solutions

Answer 18

I have the left side down and the fraction beneathe, but complicated fixing right side.
is that possible for a solution set? the answer must be two separate numbers

Answer 19

not always, quadratics have AT MOST 2 solutions but can have only one or no real solutions, this appears to be a classic no real solutions problem

Answer 20

the solutions to a quadratic are where the graph crossed the x-axis, if you graph the original problem does it cross the x-axis?

Answer 21

there is no graphing, and there is no option for no solution--there is indeed a solution. haha

Answer 22

It might make things simpler if you tell us what the original problem is.

Answer 23

it must form an equation with only addition and subraction signs between them

Answer 24

I did if you look above

Answer 25

:)

Answer 26

hello?

Answer 27

did you not understand it?

Answer 28

I understand that you have simplified the original problem but if you post what the quadratic is then we could verify that your solutions are correct.