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15 ml of a mixture of C2H4 & CH4 after oxidation with O2 gave 20 ml of CO2.Express the composition of the mixture in volume measure. a. 10 ml C2H4 , 5 ml CH4 b. 5 ml C2H4 , 10 ml CH4
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assuming everything is in the gas phase and excess O2, then the total number of C in the reactants must equal the total number of C in the products (gas volumes are proportional to molar amounts). if C2H4 is x, then CH4 is 15-x. C from C2H4 would be 2x and C from CH4 would be 15-x Assuming complete combustion (H2O is the only other product) 2x + 15 - x = 20 x = 5 ml of C2H4, 10 ml of CH4
tnx a lot!!
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