Question

determine the values of x given for which f'(x)>0, given that f(x)= 1/(4+2x^2)^4

Answer 1

that would be easier to do if you simply take and negate the exponent and work the reciprocal

Answer 2

f(x) = (4 +2x^2)^(-4)

f'(x) = -4(4 +2x^2)^(-5) 4x

Answer 3

so when x = 0; is all I see for a zero

Answer 4

-16x
----------- = 0 when x = 0
(4 +2x^2)^5

Answer 5

Real solutions anyway.

Answer 6

yes :) assumably

Answer 7

when x = 1 we get a - value; so stick with values of x<0

Answer 8

thanks!