maxima question. The question is weirdly worded. In essence, I need to determine the dimensions and maximum volume of a rectangular prism(bag) if the sum of the length, width and height can't exceed 156.
A maximized rectangular prism is a cube. Therefore, you can simply divide 156 by 3... 156/3 = 52. 52*52*52 = Max volume 52+52+52 = 156.
Thanks for quick reply. Sorry but can I ask why it has to be a cube? I will need to justify my answer for assignment paper.
The next part of school question goes on and asks what the result would be if max depth was 24 cm? or the width were half of length? I assume there must be a formula.
You can prove it many ways, I prefer calculus, but truthfully you can probably get an explanation just googling it. "Maximized rectangular prism is a cube". Now you can do 156 - 24 (for the depth) 156-24= 132 Divide 132 by 2 (2 remaining items - length and width) 66. Therefore L=66, W=66, D=24 66*66*24 = Max volume 66+66+24 =156
I will leave the last one up to you, you should be able to figure it out.
Thanks. Very helpful. Can I ask one more question: What is the best software solution to graph equations (without doing programming or paying a fortune) that look textbook like? Been stuck for ages on this.
It depends, do you go to a university? You can usually download Mathematica for students free of charge. If not, then you can use WolframAlpha (website). For example: http://www.wolframalpha.com/input/?i=x^2%2By^2%3D9 You can get 3D graphs as well, that is just an example.
Thank you
Join our real-time social learning platform and learn together with your friends!