The wind-chill index is modeled by the function below where T is the temperature (°C) and v is the wind speed (km/h). W = 13.12 + 0.6215T - 11.37v0.16 + 0.3965Tv0.16 When T = 13°C and v = 34 km/h, by how much would you expect the apparent temperature W to drop if the actual temperature decreases by 1°C? (Enter your answer to 1 decimal place.) °C What if the wind speed increases by 1 km/h?(Enter your answer to 2 decimal places.) °C
is that v^0.16??
yes
and is the apparent temp the wind chill W?
yes
I was think I would have to find W with respect of T first, but I am not sure where the less 1 degree comes in
differentiate wrt T dW/dT = 0.6215 + 0.3965 (v)^0.16 dW = [0.6215 + 0.3965 (v)^0.16] dT dT=1 hence find dW
got it??
Depening on what class this is for, you may be supposed to do this with partial derivatives, but you can actually just plug in the given T and v, and compute an initial W, then change the T or v by the one unit as requested to get a final W, then just subtract to find the difference between W values.
yeah hes right
well yes i am suppose to use partial derivatives
then do as ive done....it should work...
I am....what about the dT=1 part?
dT is the change in actual temp, which is given to be 1 degree,
got it?
yes
ok....good luck fr the others
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