Question

Use the general formula to write the area A of the enclosure as a function of w (that is, only
the variable w should appear in the function). it should be a quadratic function

Answer 1

What enclosure?

Answer 2

what is the enclosure?
are we enclosing a rectangle or something?
or can we enclose whatever we want?

Answer 3

hold on im trying to get the file of the actuall question its part of a project

Answer 4

Its to question number 5

Answer 5

I am completely lost

Answer 6

maybe this will help

Answer 7

Okay, so you have 682 feet of fencing to make up two "width sides" and one "length side" this translates to the equation:
682 = 2W + L

You know from basic geometry that the area of a rectangle is length times width:
A = L*W

What you need to do is solve the first equation for L in terms of W:
682 = 2W + L
L = 682 -2W

Then substitute that L value into the second function so that you have A in terms of just W:
A = L*W
A = (682 -2W)W

Answer 8

anyone?

Answer 9

?

Answer 10

anyone what?

Answer 11

the site froze on me im taking a look at it now

Answer 12

ok lol

Answer 13

now if i can get the window correct on my ti 84 :P

Answer 14

any help with that?

Answer 15

go to Y=

Answer 16

type 682x-2x^2

Answer 17

then go to window

Answer 18

yeah i got the equation in its just getting a clear shot of the parabola

Answer 19

go to where it says x min and type 100
go to where it says x max and type 200
go to where it says y min and type 80
go to where it says y max and type 60000
and see if it looks viewable

Answer 20

try going to the highest point on the curve and approximate what it is

Answer 21

it works but im going to need both sides of the parabola
can i just extend the xmin

Answer 22

holy crap I got it

Answer 23

no you are fine but you can if you want to

Answer 24

you are amazing!

Answer 25

did you use the maximum feature on your calculator?

Answer 26

ximn -100
xmax 400
ymin 80
ymax 60000

Answer 27

no thats not what i meant

Answer 28

do you see calc?

Answer 29

i havent taken advantage of that yet

Answer 30

lets do it

Answer 31

i got the max

Answer 32

do you see maximum

Answer 33

yeah did the whole left and right bound

Answer 34

thats going to give me the best area correct?

Answer 35

oh nice
i got (170.50001,58140.5)
this is just an appoximation
I arleady found the exact on that pdf file

Answer 36

your approximation doesn't have to be mine
but both of ours should be pretty close to the same thing
is yours close to my?

Answer 37

its exact

Answer 38

k now you remember the file i gave you right?
that vertex of the parabola i found by putting the parabola in vertex form gave me the exact (max width,max area)

Answer 39

what file

Answer 40

scroll up if you haven't seen the file and click on it

Answer 41

looking at it now

Answer 42

you remember when you uploaded a file
i uploaded a file like a few minutes afterwards

Answer 43

yeah i see it

Answer 44

if i have any more questions ill post them

Answer 45

ok make a new post though because i'm about to leave or do it so you can get someone's attention and bring them back here to help k?

Answer 46

or 3wood might come back

Answer 47

gn guys and peace

Answer 48

thanks for all the help both of you are life savers