Question

What are the retricemptotes of the hyperbola:
(x-1)^(2)/(25)-(y-4)^(2)/(16)=1

Answer 1

bx/a where b and a are the sqruare roots of your denoms

Answer 2

since the x spot is bigger; that isthe width of the rectangular asymptotes of the hyperbola

Answer 3

-5,5 the height of this rectangular thing is -4,4

Answer 4

i just noticed its off centered lol

Answer 5

(x-1)^2 (y-4)^2
-------- - ------- = 1
a^2=25 b^2=16

if this thing were centered wed have the rectangle asymptote at:

y = (4/5) x but lets put it back now

Answer 6

(y-4) = (4/5)(x-1)

y = (4/5)x - 4/5+20/5

y = (4/5)x + 16/5

Answer 7

and the other is just the negative slope of that i believe

Answer 8

so is (4/5)x+16/5 the retricepmtote?

Answer 9

if i did it right, it should be one of them; th eother would be:

y = -(4/5)x + 16/5

Answer 10

y = (b/a)x is the normal asymptote; but since this is off centered, we gotta adjust for that discrepency

Answer 11

gotta get to calc class and learn limits lol.... have fun ;)

Answer 12

it can have multiple retricepmtotes, so would it be wrriten as (4/5)x, and 16/5?