2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?
interent down, we had a bad storm roll through
yes still interested
By the way, did you realize that the phrasing of yesterdays problems were not good, and I conceived something which was not correct
For that problem on cumulative quadratic equation, .....
It meant that the equation itself provided the cumulative result
yes
So our result would be f(5)-f(4)
I am sorry, but the phrasing was too poor, and I didn't get it at all
sorry.. ok can you help me with this one?
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?
Did you actually understand the problem ?
I mean did you understand what its saying?
no because i tried to use the formula 10e^.026(20) yet I get the wrong answer
Before using the formula you must understand what its being said...
What is the precise meaning of the term "given along with r"
time
?
I don't know, but I feel that it could have been better phrased
Is it from some book?
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ? r is the 2.6
r is the decimal notation
Hey! I have the feeling you are actually phrasing the problem, it can't be from some printed material. Am I right?
thats what it says in the book, then it says write the formula PE^rx where r is the decimal notation
and that models the population in millions of years x after 1999
Listen the problem can't be solved if I don't understand the english. You see, I can't make out any thing from this part "its annual % rate of continuous growth P=10 Millions, r = 2.6% ". This is some kind of broken sentence. It makes no sense .
then it says the population in 2019 will be?
just a min I will write he whole thing and paste it correctly
Come here https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB#
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% - use the formula f(x) = PE^rx, where r is in decimal notation, that models the population in millions x years after 1999. The population in 2019 will be approximately ? million
Tell me what you wanted to say
I did it on the calc again
I did it like this 10e^(.037(20) and it came out with 17
I used extra parenthasis
(.037(20))
Yes, it is something around 16.8 ............
So is that ok?
I think so
how did you get 16.8?
So any more problem?
I just calculated using the calculator, thats it
how did you do it cause i got 17?
Come back to that place https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB&pli=1#
I am sorry there was some connection problem here, I got disconnected. Please visit the link (given on the previous post) and post your email address....
I forgot your email address
\[A=10\times e^{.026\times 20}=10 e^{.52}=16.82\] rounded. so 16.82 million
Join our real-time social learning platform and learn together with your friends!