Question

the most general solution which satisfies tan a=1, cos a=-1/sqrt()

Answer 1

\[\tan \theta=1, \cos \theta=-1/\sqrt{2}\]

Answer 2

\[\theta=\pi/4+\pi+2n \pi={5\pi \over 4}+2n \pi; n=0,1,2,..\]

Answer 3

would you explain it a bit

Answer 4

First, the angle at which tan is equal 1, and cos is 1/sqrt(2) is pi/4.

Answer 5

Then we should look for the quadrant that has positive values for tan and negative values for cos, and that would be the third quadrant.

Answer 6

So the correspondent angle for pi/4 in the third quadrant is pi/4 +pi.

Answer 7

This angle will occur again after 2n(pi) for n=0,1,2,...

Answer 8

Does that make sense?!

Answer 9

\[2n \pi +3\pi/4\] is it rite?

Answer 10

Yeah, if you have both cos and tan negatives.

Answer 11

nd id i have jus the cos -ve it wud be 5pi/4...is that correct?

Answer 12

*if

Answer 13

Exactly.

Answer 14

kool;-)