Question

7u^2-28m^2
factor the polynomial

Answer 1

\[7(u ^{2}-4m ^{2})\] \[7(u+2m)(u-2m)\]

Answer 2

do you understand how to do these type of problems?

Answer 3

yes im just checking the problems to see if people come up with the same answer as me or something different

Answer 4

ok, do you have any more?

Answer 5

i have 7 more

Answer 6

go ahead, ask away :)

Answer 7

ok thank you
this is the last thats factoring out the rest are solving the equations 16c^2+72cd+81d^2

Answer 8

this might go faster if you tell me what you got for the answer and i'll check to make sure it's correct

Answer 9

this one im thinking is prime

Answer 10

which number do you think is prime?

Answer 11

im thinking the polynomial is prime like the whole thing in other words it cant be factored down into a product of 2 binomials

Answer 12

yes. first you should reorder the polynomial so it looks like this:\[72cd+16c ^{2}+81d ^{2}\]
then factor
\[(4c+9d)(4c+9d)\]
\[(4c+9d)^{2}\]

Answer 13

50b^2+20b+2=0
im thinking the solution to this is 1/5 -1/5

Answer 14

how did you get the positive 1/5?

Answer 15

i got the negative one first and the teacher said if the negative works then the positive will work as well and the other way around

Answer 16

that's only the case when the variaable is squared or has a even number power. try plugging in the positive 1/5 in to the equation. does it come out to equal 0?

Answer 17

no so it would be -1/5 and what would the other solution be then if its not positive 1/5

Answer 18

-(1/5) is the only answer. the polynomial should look like this :\[2(25b ^{2}+10b+1)=0\]\[2(5b+1)(5b+1)=0\]\[5b+1=0\]\[b=-{\frac{1}{5}}\]

Answer 19

sorry my computer is being tarded the next one is g^2+2/3g+1/9=0

Answer 20

\[g=-{\frac{1}{3}}\]

Answer 21

okk thanks thats all i needed for now youve been helpful thank you