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Mathematics 8 Online
OpenStudy (anonymous):

differentiate: xy=[(x+3y)^4]+7

OpenStudy (anonymous):

dy / dx or dx / dy ?

OpenStudy (anonymous):

The total differential is: \[y \text{Dt}[x]+x \text{Dt}[y]=4 (x+3 y)^3 (\text{Dt}[x]+3 \text{Dt}[y]) \]

OpenStudy (anonymous):

For dy/dx solve the equation for Dt[x] \[\text{Dt}[y]=\frac{-y \text{Dt}[x]+4 (x+3 y)^3 \text{Dt}[x]}{x-12 (x+3 y)^3} \] Factor the right side for Dt[x] \[\text{Dt}[y]=\frac{\left(\left(4 x^3-y+36 x^2 y+108 x y^2+108 y^3\right) \text{Dt}[x]\right)}{x-12 (x+3 y)^3} \] Divide each side by Dt[x] \[\frac{\text{Dt}[y]}{\text{Dt}[x]}=\frac{\left(4 x^3-y+36 x^2 y+108 x y^2+108 y^3\right) }{x-12 (x+3 y)^3} \]

OpenStudy (anonymous):

Thankyou for the medal, cara.

OpenStudy (anonymous):

no problem thanks for ur help!! u do it a bit differently than my teacher so i was a bit confused at first but i figured it out lol thanks!

OpenStudy (anonymous):

Your welcome.

OpenStudy (anonymous):

As an aside, "For dy/dx solve the equation for Dt[x]" should have been typed: "For dy/dx solve the equation for Dt[y]" Very Sorry.

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