Question

trains e and w leave the same city at the same time train e travels due north at 5 miles per hour slower than train w which is traveling due east. after two hours, they are 150 miles apart. find the speed of each train to the nearest whole #

Answer 1

please help me i need this answer badly!!

Answer 2

looks relatively easy

Answer 3

distance = rate x time

Answer 4

let the speed of "train e" be x

Answer 5

now we know the speed of train w is ( x+5)

Answer 6

After two hours , train e has travelled (2x) miles ( because the time is 2hrs , and its rate is x miles/hr )

Answer 7

similarly , after two hours , train w has travelled 2(x+5) miles

Answer 8

now, one is travelling north, the other east, ie they are at right angle to one another , the distance between them represent the hypotenuse of a right angle triangle, which can be found by phytagorus

Answer 9

so [ 2x}^2 + [ 2(x+5)]^2 = 150^2

Answer 10

^ from pythagorus

Answer 11

then solve that ,

Answer 12

you get solutions x=-64.5 and x= 57.85

Answer 13

take the positive case, because we are dealing with speed

Answer 14

thanks so much for all your help you saved my life- that totally makes sense!

Answer 15

therefore speed train e is 57.85mph , and speed of traian w is 62.85mph ( ie x+5)