Question

perform the indicated operations & simplify
3z + 2z - 5
--- --- ---
z^2-1 1-z z-1

Answer 1

first you'll need to get the have the same denominator:\[\frac{3z + 2z(-(z+1)) - 5(z-1)(z+1)}{(z+1)} \]\[= \frac{3z -2z^2-2z-5z^2+5}{(z+1)(z-1)}\]\[= \frac{z-7z^2+5}{(z-1)(z+1)}\]\[=\frac{-7z^2 +z +5}{(z-1)(z+1)}\]

correct me if I'm wrong please ^_^

Answer 2

first step (z-1)(z+1) <-denominator, typo lol ^_^"

Answer 3

hmm, there's something wrong?

Answer 4

I have \[(z(-2z-4)-5)/((z+1)(z-1)\]

Answer 5

I think it has to do with the 1-z thing

Answer 6

I think your solution has a wrong sign on the numerator?

Answer 7

hmm

Answer 8

lol yeah, the 2z(-(1+z)) right|? :)

Answer 9

lol

Answer 10

it should be 2z(z+1) ._. my bad lol sorry :)

Answer 11

sorry that answer is not correct

Answer 12

?