Question

∫x/√(9+〖16x〗^2 ) dx

Answer 1

Let 9+16x^2 = t
Differentiating on both sides,

32x dx = dt

\[1/32 \int\limits_{}{} 32x dx / 9+ (16x)^2\]
=\[1/32 \int\limits_{} dt/t\]
=\[1/32 \ln(t)\]
=1/32 ln(9+16x^2)

Answer 2

amogh you very smart

if I may know what the secret

Answer 3

hahaha...jee

Answer 4

lol