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Mathematics 15 Online
OpenStudy (anonymous):

Use summation given below to find a function that it represents

OpenStudy (anonymous):

\[\sum _{n=1}^{\infty } \text{nx}^n\]

OpenStudy (anonymous):

\[x/(x-1)^2\]

OpenStudy (anonymous):

how did you get it?

OpenStudy (anonymous):

give me a second

OpenStudy (anonymous):

I will post this question again

OpenStudy (anonymous):

anything?

OpenStudy (anonymous):

yeah, sorry, busy busy, here it goes

OpenStudy (anonymous):

\[\sum_{1}^{∞}n x ^{n} = x * \sum_{1}^{∞}n x ^{n-1} = x * d/dx[\sum_{1}^{∞} x ^{n}] = x * d/dx[1/(1-x)] = x/[(1-x)^{2}]\] Excuse me for the poor formating but the website doesn't offer much of choice. The star (*) stands for multiplication. Thanks.

OpenStudy (anonymous):

Hey there's one catch: correct this: \[x * d/dx[\sum_{0}^{n} x ^{n}]\] Because when we differentiate, n->0 not n->1 Thanks

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