Question

show me how to work 4y=12y^2

Answer 1

what have you done so far?

Answer 2

-4y from each side; then factor out a y and see which y values make it equal zero

Answer 3

did you just say subtract 4y from both sides?

Answer 4

nothing i dont understand how to work it

Answer 5

yes

Answer 6

umm thats wrong.... more like divide.

Answer 7

thats what i thought it would be division

Answer 8

4y = 12y^2 ; -4y

0 = 12y^2 -4y ; factor out 4y

0 = 4y(3y - 1) ; y = 0 or 1/3

Answer 9

^2 means squared right that's why i typed it like that because 12y squared

Answer 10

so 4y=12y squared

Answer 11

am i still 'wrong' ? lol

Answer 12

oh sorry yeah do it like he said and check using quadratic.

Answer 13

ok i'm a 9th grader so i'm a bit confused lol

Answer 14

you can also /4y if you want

1 = 3y ; y=1/3 but your missing something because... 4y CAN be a zero, which this way does not allow for

Answer 15

if it can be zero; stay away from division

Answer 16

\[4y=12y^2\]\[4y-4y=4y^2-4y\]\[0=4y^2-4y\]\[4(y^2-y)=0\]\[4(y(y+1))=0\]

Answer 17

yes good thinking ^-^

Answer 18

*12y^2

Answer 19

when you know it can never be zero; then division is fine ;)

Answer 20

ok ty