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Mathematics 10 Online
OpenStudy (anonymous):

How do i turn a growth function with respect to height with respect to time into acceleration with respect to time?

OpenStudy (anonymous):

Differentiate it twice.

OpenStudy (anonymous):

differentiate time?

OpenStudy (anonymous):

wait distance / time :P

OpenStudy (anonymous):

Yeah differentiate the function with respect to time.

OpenStudy (amistre64):

height is a position derive it once to find the change in height with respect to time; which is speed, also known as velocity, or how fast the growth is. derive again to find the change in velocity, which is acceleration.

OpenStudy (amistre64):

derivatives are 'how something changes compared to something else'. Graphically, that represents slope right? how much does the y value change when you move the x?

OpenStudy (anonymous):

Well, I Have a huge problem regarding loggerpro...

OpenStudy (anonymous):

We did an experiment where we used mentos & coke in-order to investigate exponential growth patterns ect.. Now I'm struggling to realise why my raw data is linear and Ln data is exponential...

OpenStudy (anonymous):

Now this is my raw data. (I've tired to make it exponential :P

OpenStudy (amistre64):

that looks like a bounded exponential

OpenStudy (amistre64):

in other words, the data starts out looking linear, but there is a limit that it approaches

OpenStudy (anonymous):

Yeah =/

OpenStudy (anonymous):

Another picture, this is of my (initial) raw data and the Ln of height

OpenStudy (anonymous):

red = raw and blue = Ln(height)

OpenStudy (anonymous):

ignore the first graph.

OpenStudy (amistre64):

how did you obtain the data? what were the ...... ignore function activated :)

OpenStudy (anonymous):

But still... do understand what I mean?

OpenStudy (amistre64):

almost; can you show me the table that the data comes from? your experiment?

OpenStudy (anonymous):

yeah 1 sec

OpenStudy (anonymous):

OpenStudy (amistre64):

so did you come up with a good: y(s) = s function ?

OpenStudy (amistre64):

the time taken to reach the meters? what does position have to do with time?

OpenStudy (amistre64):

and of course the higher it gets the slower it goes :)

OpenStudy (anonymous):

yeah umm 1 sec

OpenStudy (amistre64):

i wrote a program that can fit this to a quadratic :)

OpenStudy (anonymous):

i got y=0.5604x-0.8171

OpenStudy (amistre64):

OpenStudy (anonymous):

Do you know how to expain it being a quadratic?

OpenStudy (anonymous):

explain*

OpenStudy (amistre64):

it would be a best fit line as well

OpenStudy (amistre64):

the most basic option would be to take the slope from one point to the next; table that up; and see what it looks like

OpenStudy (anonymous):

yeah, but the next question asks: How well do these functions fit your graphs? Are they a perfect fit? Explain your answer

OpenStudy (anonymous):

What we are meant to do is determine the function for the graphs

OpenStudy (amistre64):

perfect fit? any real life experiments are never gonna perfectly fit a model

OpenStudy (anonymous):

There is one argument :)

OpenStudy (amistre64):

models are ideals; real life experiments contain to many variables to account for

OpenStudy (anonymous):

so how do i use this quadratic program?

OpenStudy (amistre64):

you plug in three data points and it takes them to figure out the quadratic that bends to those points; then to test for accuracy, I used a feature to put in a random 'x' point to see if the quadratic is good enough

OpenStudy (amistre64):

OpenStudy (amistre64):

another option is to do a method of 'least squares' which i forget the steps to :)

OpenStudy (anonymous):

Alrighty, so ive got the quadratic: 0.807801462732185x^2 + -11.760157128268668x + 40.60929764207282

OpenStudy (anonymous):

cause what I have to do is work out the equations for each graph, preferable manually.. then predict the spray for 5 mentos.. Justify your response in mathematical reasoning..

OpenStudy (amistre64):

i didnt see a table option for 'number of mentos'

OpenStudy (amistre64):

and remember to use diet coke and the minty mentos....

OpenStudy (anonymous):

We have already conducted the experiment its just if i were able to work out 1 i'd be able to do the others :) However, for number of mentos there is one for 4/7/9

OpenStudy (anonymous):

Heheh you're my last hope now :P

OpenStudy (amistre64):

mythbusters did an episode on this menthos thing; try to check out their work :) get some ideas if you havent already

OpenStudy (amistre64):

that cut it short lol just google mythbusters mentos

OpenStudy (anonymous):

No idea if this is allowed, but do you use skype?

OpenStudy (amistre64):

aint got the periphials for it.....

OpenStudy (anonymous):

I just want to screen share or something :L

OpenStudy (amistre64):

do you know how to draw a vector field?

OpenStudy (anonymous):

Nope.

OpenStudy (amistre64):

you strat out with something like this; and for each point you find the slope (y/x) and plug a vector representation of it at the point to see where the data is moving

OpenStudy (amistre64):

and watch it move :)

OpenStudy (amistre64):

they prolly have online stuff to do it quicker and easier tho

OpenStudy (amistre64):

in fact, they proly have online best fit calculators too :)

OpenStudy (anonymous):

O i can best bit in autograph, its just.. I need to beable to work it out manually. :C

OpenStudy (amistre64):

manually can be a pain; especially with alot of data points and decimals involved; that reason we have computers is to use as a tool to help us; it aint a cheat ya know :)

OpenStudy (amistre64):

they teach you the manually so that you have the concept of why it works and how to get to an answer when you aint got the tools avaiable; but before computers it took alot of good mena dnwomen and a few good trout many years to do a single math problem

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