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Mathematics 8 Online
OpenStudy (anonymous):

what is a function? just a simple question. who can answer?

OpenStudy (amistre64):

a function is defined as for any one input; there is only one output that can be produced

OpenStudy (amistre64):

a relation exists between any given sets of data; but a function is useful in that we can use it to predict events

OpenStudy (anonymous):

ahaa tnx

OpenStudy (anonymous):

Let A and B be sets of numbers. A function f is a rule that assigns each element of A to a unique element of B.

OpenStudy (anonymous):

what if B has infinitely many element from A ., is that can be called as a function?

OpenStudy (amistre64):

If A results in many B's then a relation exists; but not a function

OpenStudy (amistre64):

If B results from multiple A's, then a function can be determined to best match the results

OpenStudy (anonymous):

*an

OpenStudy (anonymous):

how is it done?

OpenStudy (anonymous):

give all the functions. A={1,2,3} B={d,f}

OpenStudy (anonymous):

There are infinitely many.

OpenStudy (anonymous):

prove it.

OpenStudy (amistre64):

are you mapping A into B?

OpenStudy (amistre64):

f:A -> B

OpenStudy (anonymous):

f:A->B

OpenStudy (anonymous):

Let A={x: x=1,2 or 3} and B={d or f}. Then\[f:A \rightarrow B \] where f can be any function.

OpenStudy (anonymous):

Can you show it for me all the functions?

OpenStudy (anonymous):

No. And here are some corrections: B={g(x): g(x)=d or f} and g: A -> B.

OpenStudy (anonymous):

Suppose that the set C containing all g such that g: x -> g(x) (where x is in A and g(x) is in B) is finite. Then there exists a h in C such that h: x -> h(x), where h(x) is in B. But h1= h(x)+1-1 is also in C, and so is h2=h1+1-1, and so is h3=h2+1-1, . . . Therefore, C is infinite. This is a contradiction. Therefore, C must be infinite.

OpenStudy (anonymous):

And therefore there are infinitely many g.

OpenStudy (anonymous):

No: wait. I have made an error. Two function are the same if their domains (A in this case), codomains (B), and effects are the same. Thus h=h1=h2= . . . However, I still cannot list all functions g by the same argument as in the above comment. Can you see why?

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