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find x such that the distance between the points is 5. (0,0),(x, -4)
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i applied the distance formula, setting it equal to 5
or just use a vector
distance formula is the same either way
x^2 + 16 = 26 x = 3 or -3
and by 26 i mean 25
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\[\sqrt{{x^2} + 4^2} = 5\]
right; now square both sides; or simply forgo that steps by doing it in your mind :)
right so we get: x = +-3
I thought if i applied the distance formula again with x = 3, i should get 5
you will
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9+16 = 5^2 25 = 25
right i see, thank you!
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