A particles position as a function of time is given by u = cos 2t i+sin 2t j ( The u, i and j should have tilde's underneath as they are vectors) (a) find the equation of the path
x = cos(2t) y = sin(2t) z = 0
thats not the answer i sorta know how to do it but the 2t throws me off abit
thats the equation of a line in R^3 :) well, except for an initial point
the position path just produces a unit circle
yes i understand that but normally you would eliminiate the sin and cos by squaring x and y then adding them
im not sure what happens to the 2t
2t just modifies the speed of rotation; nothing more
its going twice as fast around the unit circle
i see so the working is like this; x = cos 2t y=sin2t x^2=cos^2t y^2=sin^2t x^2+y^2=1 i ignore the 2t correct
or simply redefine it; 2t = u
it has no importance on position; other than it a given t it is at this location; but the path remains unchaged by it
tell me; does a person walking along the sidewalk get to the same place as the person jogging on the sidewalk?
yes thats correct. thanks so much you actually made me understand the question.
youre welcome :)
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