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Mathematics 11 Online
OpenStudy (anonymous):

1. An animal clinic kept record of the life spans of certain poodles. The number of years the dogs lived are 8, 10, 12, 15, 17, and 13. What is the standard deviation of the poodle life spans?

OpenStudy (anonymous):

do you know the standard deviation formula?

OpenStudy (anonymous):

it should be around the sqrt(102/10)

OpenStudy (anonymous):

whats the formula

OpenStudy (anonymous):

phinx828--go back to the other question

OpenStudy (yuki):

to find the SD, you need to know the formula \[\sqrt({1 \over n} \sum {(x*-x_i)^2})\]

OpenStudy (anonymous):

sqrt(107/10)*

OpenStudy (anonymous):

Here!

OpenStudy (anonymous):

thats confusing, i never saw that formula

OpenStudy (yuki):

usually the steps are as follows 1), find x* which is the mean 2), list the square of mean deviations in your case, x*-8, x*-10, x*-12 ...etc 3), square each numbers you got in the list (x*-8)^2, (x*-10)^2, ... etc 4), add them up 5), divide them by the number of #s, in your case since you have 6 numbers, divide by 6 at this step, you will get a number called the "variant" SD is defined as the square root of the variant, so 6), square root the number you got

OpenStudy (yuki):

rosette, do you need explanation how the formula works ?

OpenStudy (anonymous):

no

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